JEE MAIN - Physics (2022 - 28th June Morning Shift - No. 25)
The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be _____________ J. (Given R = 8.31 J/mol.K)
Хариулт
7479
Тайлбар
$$U = 2\left( {{3 \over 2}R} \right)300$$
$$ = 3 \times 8.31 \times 300$$
$$ = 7479$$ J